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General Mathematics Paper 2,May/June. 2007  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 Main
General Comments
Weakness/Remedies
Strength














question 4

Y is 60 km away from X on a bearing of 135°. Z is 80 km away from
X on a bearing of 225°. Find the:

(a) distance of Z from Y;
(b) bearing of Z from Y.


_____________________________________________________________________________________________________
Observation

This question was well attempted by the candidates though many could not draw the diagram correctly.  The diagram actually reduced to a right   angled   triangle   with   |ZY|  as   hypothenus.  Hence   ZY   
=       √ 802  +  602   =   100 km.  The angle between  XY and ZY 
=   tan-1  (80/60)  =  53.12°.  Thus   the   bearing   of   Z  from  Y  is   given    by 315 – 53.12  =  261.88°.



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