Most candidates performed well in this question.  They were able to substitute correctly real numbers to find g[g(- 3)].  The values of g[f(x)]and f[g(x)] were correctly evaluated by most candidates.

            g[g(x)]  = g(3x – 7) = 3(3x – 7) – 7  =  9x  - 28
            \ g[g(-3)] =  - 27 – 28  =   - 55
            g[f(x)] =  g(2x2 – 3x – 5) = 3(2x² – 3x – 5) – 7 = 6x2 – 9x – 22
            f[g(x)] = f(3x – 7)  =  18x²  - 93x + 114