This was a question on coordinate geometry. Candidates were expected to differentiate y = x3 – 4x to get dy/dx = 3x2 – 4, substitute the value x = 1 to get the slope of line at the point x = 1 whissch is –1. At x = –1, y = -3. Thus the equation of the tangent become y + 3 = -1(x – 1) » y + x + 2 = 0. Most candidates who attempted this question performed well and scored full marks.
