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Applied Electricity Paper 2 , May/June 2007  
Questions:   1 2 3 4 5 6   Main
General Comments
Weakness/Remedies
Strength











































question 2

a) What is a magnetic field?
(b) A coil of 400 turns is wound uniformly on a ring of non-magnetic material. The ring has a mean circumference of 40 cm and a uniform cross sectional area of 4 cm2. If the current in the coil is 5 A, calculate the
(i) Magnetic field strength;
(ii) Flux density; .
(iv) . Total magnetic flux in the ring.

[permeability of free space μo = 4∏X 10-7]

_____________________________________________________________________________________________________
OBSERVATION
(a) Magnetic field - is the area/region/space around a magnet within which the magnetic effect is felt.
(b) Length of ring (L) - 40 X 10-2m
Cross sectional area (A) = 4 x 10-4m
Permeability of free space ( μo ) = 4∏X 10-7 .. ,
Number of turns (N) = 400 ..
Current (I) = 5A .';
(i) Magnetic flux strength, H = NI
                                                       L
H = 400 x 5
       40 x 10-2

H = 500A/m
(ii) Flux density (B) = μoH
                                   =4 X 10-7X 5000

Flux density (B) =6.3 x 10-3 T

(iii) Total magnetic flux (~)
..
μoH
4 X 10-7X 5000

6.3 x 10-3 T
= BA
= 6.283 x 10-3 x 4 x 10-4
= 2.513 X 10-4Wb
This question was on electromagnetic field. Many candidates attempted this question. The performance was fair enough.
In part (b) of the question, the computation of H, B and Φ was dreaded by many candidates.Just a few of them attempted the (b) part..

This question was on electromagnetic field. Many candidates attempted this question. The performance was fair enough.
In part (b) of the question, the computation of H, B and Φ was dreaded by many candidates.Just a few of them attempted the (b) part.. .
The expected answers were:


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