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Agricultural Science Paper 2, Nov/Dec 2007  
Questions: 1 2 3 4 5 6 7 8 9 10 Main
General Comments
Weakness/Remedies
Strength



























































Question 5

(a) Define crop rotation.
(b) List six factors a farmer should consider when planning a. crop rotation programme. [2 marks]
[6 marks]
 (c) If the rate of application of compost is 40 tonnes per hectare, and the size of the farmland measures 60 m by 30 m, how many kg of compost· would be required to manure a cassava subplot in a 4-comse rotation?  [8 marks]                           

                                                                      
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OBSERVATION

Majority of the candidates attempted this question and their performance was above average . . In question· 5( a) and 5(b), many candidates were able to define crop rotation -and list the factors a farmer should consider when planning a crop rotation programme.
However in question 5( c), most candidates could not calculate the kilogrammes of compost that would be required to manure a cassava sub-plot in a 4-course rotation.
The expected answers include:
.. :,.
Method 1
The area of the plot = 60 m x 30 m = 1,800m2
In a 4 - course rotation the area of the cassava sub-plot
                         =     1800m2
                                     4
                         =      450m2
1 hectare = 10,000m2 :.450m2 = 450m2
                                                       10000m2         = 0.045 hectare
1 hectare requires 40 tonnes of compost
.'. 0.045 hectare requires
40 x 0.045 tonne = 1.8 tonnes
        1
1 tonne = 1000 kg
1.8 tonnes = 1S x 1000kg .
= 1,800kg of compost

OR

Method 2
The area of the plot = 60m x 30m
                          =1800m2

 1 hectare        = 10,000m2

 Area of plot in hectare = 1800m2
                                            10,000m2
                                           
                                           =0.18 hectare

Area of cassava sub-plot = 0.18 hectare
                                                       4
                                = 0.045 hectare

I hectare requires 40 tonnes of compost

 0.18 hectare requires 40 x 0.18
                        =7.2 tonnes of compost

   .'. Cassava sub-plot requires 7.2 tonnes 4
                                       =               1.8 tonnes
I tonne = 1,000kg
 1.8 tonnes = 1.8 x1000kg
            = 1,800kg of compost

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